Ferrari F-355 Aerodynamics |

S = (77.5 x 44.5) / 144S = 23.95 square feet We'll call this 24 square feet. All this analysis will take place at the maximum speed of the vehicle, using Imperial units. The dynamic pressure at the maximum vehicle speed is; Q = 0.5 x rho x V x Vwhere rho = air density = 0.002378 slugs per cubic foot, so, Q = 0.5 x 0.002378 x (270 x 270)Q = 86.68 pounds per square foot Now we need to determine the total drag of the vehicle at its maximum speed. D = Cd x S x QD = 0.35 x 24.0 x 86.68 = 728 pounds We need to make an estimate of the drag of the open headlights. We'll assume the headlights have a physical size of about 8 inches by 10 inches each. This is then, (8.0 x 10.0) / 144 = 0.55 square
foot per headlightWe can assume Cd = 1.0 for the
flat vertical surface of each light, so the drag is;D = Cd x S x Q D = 1.0 x 0.55 x
86.68 per lightD = 47.7 pounds per light, or 95.3 pounds in total We can now calculate a new top speed due to this slight increase in drag. The drag of a car varies as the square of its velocity. Taking proportions; (D2 / D1) = (V2 x V2) / (V1 x V1)V2 = sqrt(( 270 x 270) x (728 / (728 + 95.3)) V2 = 253.8 feet per second So the maximum vehicle speed with lights open is 254 fps, compared to 270 fps with the lights closed. The open lights result in a degradation in maximum speed of 16 feet per second (10.9 mph). Finally, just to do a bit of a check on this analysis, estimating the vehicle drag based on engine power gives the following result; D = (550 x P ) / VD = (550 x 375 x 0.95) / 270 D = 725.7 pounds (compared to 728 pounds
determined previously)Note that we take the 375 horsepower maximum engine power here and apply a 0.95 factor to it, to allow for drivetrain losses. Finally, we can check the drag coefficient; Cd x S = (2 x D) / (rho x V x V)Cd x S = (2 x 725.7) / (0.002378 x 270 x 270) Cd x S = 8.37 square feet So, Cd = 8.37 / 24.0 = 0.349 (compared
to 0.35 from independent sources) |

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